$$ \begin{aligned} 5-3(x-1) &= 2x+10&& \text{simplify left side} \\[1 em]5-(3x-3) &= 2x+10&& \\[1 em]5-3x+3 &= 2x+10&& \\[1 em]-3x+8 &= 2x+10&& \text{move the $ \color{blue}{ 2x } $ to the left side and $ \color{blue}{ 8 }$ to the right} \\[1 em]-3x-2x &= 10-8&& \text{simplify left and right hand side} \\[1 em]-5x &= 2&& \text{ divide both sides by $ -5 $ } \\[1 em]x &= -\frac{2}{5}&& \\[1 em] \end{aligned} $$

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