Question
$$5-2(3x-1)-4x(2x+3) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 9 }{ 8 }-\dfrac{\sqrt{ 137 }}{ 8 } & x_2 = -\dfrac{ 9 }{ 8 }+\dfrac{\sqrt{ 137 }}{ 8 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 5-2(3x-1)-4x(2x+3) &= 0&& \text{simplify left side} \\[1 em]5-(6x-2)-(8x^2+12x) &= 0&& \\[1 em]5-6x+2-(8x^2+12x) &= 0&& \\[1 em]-6x+7-(8x^2+12x) &= 0&& \\[1 em]-6x+7-8x^2-12x &= 0&& \\[1 em]-8x^2-18x+7 &= 0&& \\[1 em] \end{aligned} $$
$ -8x^{2}-18x+7 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver