$$ \begin{aligned} 5\cdot(4-2x)+5 &= 2x-7\cdot(3+x)&& \text{simplify left and right hand side} \\[1 em]20-10x+5 &= 2x-(21+7x)&& \\[1 em]-10x+25 &= 2x-21-7x&& \\[1 em]-10x+25 &= -5x-21&& \text{move the $ \color{blue}{ -5x } $ to the left side and $ \color{blue}{ 25 }$ to the right} \\[1 em]-10x+5x &= -21-25&& \text{simplify left and right hand side} \\[1 em]-5x &= -46&& \text{ divide both sides by $ -5 $ } \\[1 em]x &= \frac{-46}{-5}&& \\[1 em]x &= \frac{46}{5}&& \\[1 em] \end{aligned} $$

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