Question
$$5(y-3)^2 = 0$$
Answer
$$ y = 3 $$
Explanation
$$ \begin{aligned} 5(y-3)^2 &= 0&& \text{simplify left side} \\[1 em]5(1y^2-6y+9) &= 0&& \\[1 em]5y^2-30y+45 &= 0&& \\[1 em] \end{aligned} $$
$ 5x^{2}-30x+45 = 0 $ is a quadratic equation.
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