$$ \begin{aligned} 5(x-2)+3 &= x+9&& \text{simplify left side} \\[1 em]5x-10+3 &= x+9&& \\[1 em]5x-7 &= x+9&& \text{move the $ \color{blue}{ x } $ to the left side and $ \color{blue}{ -7 }$ to the right} \\[1 em]5x-x &= 9+7&& \text{simplify left and right hand side} \\[1 em]4x &= 16&& \text{ divide both sides by $ 4 $ } \\[1 em]x &= \frac{16}{4}&& \\[1 em]x &= 4&& \\[1 em] \end{aligned} $$

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