Question
$$5(3x+1)^2+6(3x+1)-8 = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = -\dfrac{ 1 }{ 15 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 5(3x+1)^2+6(3x+1)-8 &= 0&& \text{simplify left side} \\[1 em]5(9x^2+6x+1)+6(3x+1)-8 &= 0&& \\[1 em]45x^2+30x+5+18x+6-8 &= 0&& \\[1 em]45x^2+48x+11-8 &= 0&& \\[1 em]45x^2+48x+3 &= 0&& \\[1 em] \end{aligned} $$
$ 45x^{2}+48x+3 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver