$$ \begin{aligned} 5(3x-4)+11 &= 12x&& \text{simplify left side} \\[1 em]15x-20+11 &= 12x&& \\[1 em]15x-9 &= 12x&& \text{move the $ \color{blue}{ 12x } $ to the left side and $ \color{blue}{ -9 }$ to the right} \\[1 em]15x-12x &= 9&& \text{simplify left side} \\[1 em]3x &= 9&& \text{ divide both sides by $ 3 $ } \\[1 em]x &= \frac{9}{3}&& \\[1 em]x &= 3&& \\[1 em] \end{aligned} $$

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