$$ \begin{aligned} 5\cdot(3-x) &= 3(x+5)&& \text{simplify left and right hand side} \\[1 em]15-5x &= 3x+15&& \\[1 em]-5x+15 &= 3x+15&& \text{move the $ \color{blue}{ 3x } $ to the left side and $ \color{blue}{ 15 }$ to the right} \\[1 em]-5x-3x &= 15-15&& \text{simplify left and right hand side} \\[1 em]-8x &= 0&& \text{ divide both sides by $ -8 $ } \\[1 em]x &= \frac{0}{-8}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$

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