$$ \begin{aligned} 5(2^2-5)+4x\cdot3^2-15x\cdot2 &= 0&& \text{simplify left side} \\[1 em]5(2^2-5)+4x\cdot3^2-30x &= 0&& \\[1 em]5\cdot(4-5)+4x\cdot9-30x &= 0&& \\[1 em]5\cdot(-1)+36x-30x &= 0&& \\[1 em]-5+36x-30x &= 0&& \\[1 em]6x-5 &= 0&& \text{ move the constants to the right } \\[1 em]6x &= 5&& \text{ divide both sides by $ 6 $ } \\[1 em]x &= \frac{5}{6}&& \\[1 em] \end{aligned} $$

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