$$ \begin{aligned} 4y+2 &= 4^2y-3&& \text{simplify right side} \\[1 em]4y+2 &= 16y-3&& \text{move the $ \color{blue}{ 16y } $ to the left side and $ \color{blue}{ 2 }$ to the right} \\[1 em]4y-16y &= -3-2&& \text{simplify left and right hand side} \\[1 em]-12y &= -5&& \text{ divide both sides by $ -12 $ } \\[1 em]y &= \frac{-5}{-12}&& \\[1 em]y &= \frac{5}{12}&& \\[1 em] \end{aligned} $$

This page was created using