$$ \begin{aligned} 4y\cdot\frac{3}{3}-5y\cdot\frac{3}{6} &= 0&& \text{multiply ALL terms by } \color{blue}{ 6 }. \\[1 em]64y\cdot\frac{3}{3}-65y\cdot\frac{3}{6} &= 6\cdot0&& \text{cancel out the denominators} \\[1 em]24y-15y &= 0&& \text{simplify left side} \\[1 em]9y &= 0&& \text{ divide both sides by $ 9 $ } \\[1 em]y &= \frac{0}{9}&& \\[1 em]y &= 0&& \\[1 em] \end{aligned} $$

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