Question
$$4 \cdot \frac{y^3}{3}-5\frac{y^3}{6} = 0$$
Answer
$$ y = 0 $$
Explanation
$$ \begin{aligned} 4 \cdot \frac{y^3}{3}-5\frac{y^3}{6} &= 0&& \text{multiply ALL terms by } \color{blue}{ 6 }. \\[1 em]6\cdot4 \cdot \frac{y^3}{3}-6\cdot5\frac{y^3}{6} &= 6\cdot0&& \text{cancel out the denominators} \\[1 em]8y^3-5y^3 &= 0&& \text{simplify left side} \\[1 em]3y^3 &= 0&& \\[1 em] \end{aligned} $$
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