Question
$$4x\cdot3+14x\cdot2-6x-12 = 0$$
Answer
$$ x = \dfrac{6}{17} $$
Explanation
$$ \begin{aligned} 4x\cdot3+14x\cdot2-6x-12 &= 0&& \text{simplify left side} \\[1 em]12x+28x-6x-12 &= 0&& \\[1 em]34x-12 &= 0&& \text{ move the constants to the right } \\[1 em]34x &= 12&& \text{ divide both sides by $ 34 $ } \\[1 em]x &= \frac{12}{34}&& \\[1 em]x &= \frac{6}{17}&& \\[1 em] \end{aligned} $$
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