$$ \begin{aligned} 4x-3 &= x+9&& \text{move the $ \color{blue}{ x } $ to the left side and $ \color{blue}{ -3 }$ to the right} \\[1 em]4x-x &= 9+3&& \text{simplify left and right hand side} \\[1 em]3x &= 12&& \text{ divide both sides by $ 3 $ } \\[1 em]x &= \frac{12}{3}&& \\[1 em]x &= 4&& \\[1 em] \end{aligned} $$
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