$$ \begin{aligned} 4x-2(x+5)\cdot4-3(x+6) &= 0&& \text{simplify left side} \\[1 em]4x-(2x+10)\cdot4-(3x+18) &= 0&& \\[1 em]4x-(8x+40)-(3x+18) &= 0&& \\[1 em]4x-8x-40-(3x+18) &= 0&& \\[1 em]-4x-40-(3x+18) &= 0&& \\[1 em]-4x-40-3x-18 &= 0&& \\[1 em]-7x-58 &= 0&& \text{ move the constants to the right } \\[1 em]-7x &= 58&& \text{ divide both sides by $ -7 $ } \\[1 em]x &= -\frac{58}{7}&& \\[1 em] \end{aligned} $$

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