Question
$$4x^2-38 = 43$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 9 }{ 2 } & x_2 = -\dfrac{ 9 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 4x^2-38 &= 43&& \text{move all terms to the left hand side } \\[1 em]4x^2-38-43 &= 0&& \text{simplify left side} \\[1 em]4x^2-81 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-81 = 0 $ is a quadratic equation.
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