Question
$$4 \cdot \frac{x}{x}x-25 = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = \dfrac{ 25 }{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 4 \cdot \frac{x}{x}x-25 &= 0&& \text{multiply ALL terms by } \color{blue}{ x }. \\[1 em]x4 \cdot \frac{x}{x}x-x\cdot25 &= x\cdot0&& \text{cancel out the denominators} \\[1 em]4x^2-25x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 4x^{2}-25x = 0 } $, first we need to factor our $ x $.
$$ 4x^{2}-25x = x \left( 4x-25 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 4x-25 = 0$.
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