$$ \begin{aligned} 4x\cdot(2+3)-(7-\frac{6}{2})^2 &= 0&& \text{multiply ALL terms by } \color{blue}{ 2 }. \\[1 em]24x\cdot(2+3)-2(7-\frac{6}{2})^2 &= 2\cdot0&& \text{cancel out the denominators} \\[1 em]40x-32 &= 0&& \text{ move the constants to the right } \\[1 em]40x &= 32&& \text{ divide both sides by $ 40 $ } \\[1 em]x &= \frac{32}{40}&& \\[1 em]x &= \frac{4}{5}&& \\[1 em] \end{aligned} $$

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