$$ \begin{aligned} 4a+\frac{1}{3} &= 1&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3\cdot4a+3\cdot\frac{1}{3} &= 3\cdot1&& \text{cancel out the denominators} \\[1 em]12a+1 &= 3&& \text{ move 1 to the right } \\[1 em]12a &= 3-1&& \\[1 em]12a &= 2&& \text{ divide both sides by $ 12 $ } \\[1 em]a &= \frac{2}{12}&& \\[1 em]a &= \frac{1}{6}&& \\[1 em] \end{aligned} $$

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