Question
$$4(x+1)(x+2) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = -2 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 4(x+1)(x+2) &= 0&& \text{simplify left side} \\[1 em](4x+4)(x+2) &= 0&& \\[1 em]4x^2+8x+4x+8 &= 0&& \\[1 em]4x^2+12x+8 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+12x+8 = 0 $ is a quadratic equation.
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