Question
$$4 = 3a-a^2$$
Answer
$$ \begin{matrix}a_1 = \dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 7 }}{ 2 }i & a_2 = \dfrac{ 3 }{ 2 }-\dfrac{\sqrt{ 7 }}{ 2 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 4 &= 3a-a^2&& \text{simplify right side} \\[1 em]4 &= -a^2+3a&& \text{move all terms to the left hand side } \\[1 em]4+a^2-3a &= 0&& \text{simplify left side} \\[1 em]a^2-3a+4 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-3x+4 = 0 $ is a quadratic equation.
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