Question
$$4^2\cdot2+7-(3^2-5) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 4^2\cdot2+7-(3^2-5) &= 0&& \text{simplify left side} \\[1 em]16\cdot2+7-(9-5) &= 0&& \\[1 em]32+7-4 &= 0&& \\[1 em]32+3 &= 0&& \\[1 em]35 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 35 = 0 } $ is FALSE, we conclude that the equation has no solution.
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