$$ \begin{aligned} \frac{4}{x}-3 &= x&& \text{multiply ALL terms by } \color{blue}{ x }. \\[1 em]x\cdot\frac{4}{x}-x\cdot3 &= xx&& \text{cancel out the denominators} \\[1 em]4-3x &= x^2&& \text{move all terms to the left hand side } \\[1 em]4-3x-x^2 &= 0&& \text{simplify left side} \\[1 em]-x^2-3x+4 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}-3x+4 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver