$$ \begin{aligned} \frac{4}{x}-2+\frac{2}{x}-3 &= 0&& \text{multiply ALL terms by } \color{blue}{ x }. \\[1 em]x\cdot\frac{4}{x}-x\cdot2+x\cdot\frac{2}{x}-x\cdot3 &= x\cdot0&& \text{cancel out the denominators} \\[1 em]4-2x+2-3x &= 0&& \text{simplify left side} \\[1 em]-5x+6 &= 0&& \text{ move the constants to the right } \\[1 em]-5x &= -6&& \text{ divide both sides by $ -5 $ } \\[1 em]x &= \frac{-6}{-5}&& \\[1 em]x &= \frac{6}{5}&& \\[1 em] \end{aligned} $$

This page was created using