$$ \begin{aligned} \frac{4}{3}(x+\frac{3}{4}) &= 5&& \text{simplify left side} \\[1 em]\frac{4}{3}\frac{4x+3}{4} &= 5&& \\[1 em]\frac{4x+3}{3} &= 5&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3 \cdot \frac{4x+3}{3} &= 3\cdot5&& \text{cancel out the denominators} \\[1 em]4x+3 &= 15&& \text{ move 3 to the right } \\[1 em]4x &= 15-3&& \\[1 em]4x &= 12&& \text{ divide both sides by $ 4 $ } \\[1 em]x &= \frac{12}{4}&& \\[1 em]x &= 3&& \\[1 em] \end{aligned} $$

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