Question
$$4(x+5)^2-1 = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 9 }{ 2 } & x_2 = -\dfrac{ 11 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 4(x+5)^2-1 &= 0&& \text{simplify left side} \\[1 em]4(x^2+10x+25)-1 &= 0&& \\[1 em]4x^2+40x+100-1 &= 0&& \\[1 em]4x^2+40x+99 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+40x+99 = 0 $ is a quadratic equation.
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