Question
$$4(x+2)-15-7\cdot(4-x) = 0$$
Answer
$$ x = \dfrac{35}{11} $$
Explanation
$$ \begin{aligned} 4(x+2)-15-7\cdot(4-x) &= 0&& \text{simplify left side} \\[1 em]4x+8-15-(28-7x) &= 0&& \\[1 em]4x-7-(28-7x) &= 0&& \\[1 em]4x-7-28+7x &= 0&& \\[1 em]11x-35 &= 0&& \text{ move the constants to the right } \\[1 em]11x &= 35&& \text{ divide both sides by $ 11 $ } \\[1 em]x &= \frac{35}{11}&& \\[1 em] \end{aligned} $$
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