Question
$$4(n-3)^2 = 0$$
Answer
$$ n = 3 $$
Explanation
$$ \begin{aligned} 4(n-3)^2 &= 0&& \text{simplify left side} \\[1 em]4(1n^2-6n+9) &= 0&& \\[1 em]4n^2-24n+36 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-24x+36 = 0 $ is a quadratic equation.
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