Question
$$4(c+3)-(c-1) = 64$$
Answer
$$ c = 17 $$
Explanation
$$ \begin{aligned} 4(c+3)-(c-1) &= 64&& \text{simplify left side} \\[1 em]4c+12-(c-1) &= 64&& \\[1 em]4c+12-c+1 &= 64&& \\[1 em]3c+13 &= 64&& \text{ move 13 to the right } \\[1 em]3c &= 64-13&& \\[1 em]3c &= 51&& \text{ divide both sides by $ 3 $ } \\[1 em]c &= \frac{51}{3}&& \\[1 em]c &= 17&& \\[1 em] \end{aligned} $$
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