$$ \begin{aligned} 4(3y-1)+13 &= 5y+2&& \text{simplify left side} \\[1 em]12y-4+13 &= 5y+2&& \\[1 em]12y+9 &= 5y+2&& \text{move the $ \color{blue}{ 5y } $ to the left side and $ \color{blue}{ 9 }$ to the right} \\[1 em]12y-5y &= 2-9&& \text{simplify left and right hand side} \\[1 em]7y &= -7&& \text{ divide both sides by $ 7 $ } \\[1 em]y &= -\frac{7}{7}&& \\[1 em]y &= -1&& \\[1 em] \end{aligned} $$

This page was created using