$$ \begin{aligned} 3y-7+1 &= y&& \text{simplify left side} \\[1 em]3y-6 &= y&& \text{move the $ \color{blue}{ y } $ to the left side and $ \color{blue}{ -6 }$ to the right} \\[1 em]3y-y &= 6&& \text{simplify left side} \\[1 em]2y &= 6&& \text{ divide both sides by $ 2 $ } \\[1 em]y &= \frac{6}{2}&& \\[1 em]y &= 3&& \\[1 em] \end{aligned} $$
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