Question
$$3y-7(-y+6) = 0$$
Answer
$$ y = \dfrac{21}{5} $$
Explanation
$$ \begin{aligned} 3y-7(-y+6) &= 0&& \text{simplify left side} \\[1 em]3y-(-7y+42) &= 0&& \\[1 em]3y+7y-42 &= 0&& \\[1 em]10y-42 &= 0&& \text{ move the constants to the right } \\[1 em]10y &= 42&& \text{ divide both sides by $ 10 $ } \\[1 em]y &= \frac{42}{10}&& \\[1 em]y &= \frac{21}{5}&& \\[1 em] \end{aligned} $$
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