Question
$$3x\cdot\frac{4}{3}x\cdot4-3+4 = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 4 } i & x_2 = -\dfrac{ 1 }{ 4 } i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3x\cdot\frac{4}{3}x\cdot4-3+4 &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]33x\cdot\frac{4}{3}x\cdot4-3\cdot3+3\cdot4 &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]48x^2-9+12 &= 0&& \text{simplify left side} \\[1 em]48x^2+3 &= 0&& \\[1 em] \end{aligned} $$
$ 48x^{2}+3 = 0 $ is a quadratic equation.
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