Question
$$3x\cdot2+3(x+4)x = 3$$
Answer
$$ \begin{matrix}x_1 = -3-\sqrt{ 10 } & x_2 = -3+\sqrt{ 10 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3x\cdot2+3(x+4)x &= 3&& \text{simplify left side} \\[1 em]6x+3(x+4)x &= 3&& \\[1 em]6x+(3x+12)x &= 3&& \\[1 em]6x+3x^2+12x &= 3&& \\[1 em]3x^2+18x &= 3&& \text{move all terms to the left hand side } \\[1 em]3x^2+18x-3 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+18x-3 = 0 $ is a quadratic equation.
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