$$ \begin{aligned} 3x-3(2x+3) &= 0&& \text{simplify left side} \\[1 em]3x-(6x+9) &= 0&& \\[1 em]3x-6x-9 &= 0&& \\[1 em]-3x-9 &= 0&& \text{ move the constants to the right } \\[1 em]-3x &= 9&& \text{ divide both sides by $ -3 $ } \\[1 em]x &= -\frac{9}{3}&& \\[1 em]x &= -3&& \\[1 em] \end{aligned} $$
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