Question
$$3x^2-5 = 1$$
Answer
$$ \begin{matrix}x_1 = -\sqrt{ 2 } & x_2 = \sqrt{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3x^2-5 &= 1&& \text{move all terms to the left hand side } \\[1 em]3x^2-5-1 &= 0&& \text{simplify left side} \\[1 em]3x^2-6 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-6 = 0 $ is a quadratic equation.
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