Question
$$3x \cdot \frac{2}{3}x\cdot6+\frac{\frac{7}{1}}{3} = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{\sqrt{ 7 }}{ 6 } i & x_2 = - \dfrac{\sqrt{ 7 }}{ 6 } i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3x \cdot \frac{2}{3}x\cdot6+\frac{\frac{7}{1}}{3} &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]33x \cdot \frac{2}{3}x\cdot6+3\frac{\frac{7}{1}}{3} &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]36x^2+7 &= 0&& \\[1 em] \end{aligned} $$
$ 36x^{2}+7 = 0 $ is a quadratic equation.
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