Question
$$3n^2-5 = -33$$
Answer
$$ \begin{matrix}n_1 = \dfrac{ 2 \sqrt{ 21}}{ 3 } i & n_2 = -2 \dfrac{\sqrt{ 21 }}{ 3 } i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3n^2-5 &= -33&& \text{move all terms to the left hand side } \\[1 em]3n^2-5+33 &= 0&& \text{simplify left side} \\[1 em]3n^2+28 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+28 = 0 $ is a quadratic equation.
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