$$ \begin{aligned} 3c+1 &= c+1&& \text{move the $ \color{blue}{ c } $ to the left side and $ \color{blue}{ 1 }$ to the right} \\[1 em]3c-c &= 1-1&& \text{simplify left and right hand side} \\[1 em]2c &= 0&& \text{ divide both sides by $ 2 $ } \\[1 em]c &= \frac{0}{2}&& \\[1 em]c &= 0&& \\[1 em] \end{aligned} $$
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