Question
$$3b(2b+4) = 150+12b$$
Answer
$$ \begin{matrix}b_1 = 5 & b_2 = -5 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3b(2b+4) &= 150+12b&& \text{simplify left and right hand side} \\[1 em]6b^2+12b &= 12b+150&& \text{move all terms to the left hand side } \\[1 em]6b^2+12b-12b-150 &= 0&& \text{simplify left side} \\[1 em]6b^2+12b-12b-150 &= 0&& \\[1 em]6b^2-150 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}-150 = 0 $ is a quadratic equation.
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