Question
$$36 = (z-2)^2$$
Answer
$$ \begin{matrix}z_1 = -4 & z_2 = 8 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 36 &= (z-2)^2&& \text{simplify right side} \\[1 em]36 &= z^2-4z+4&& \text{move all terms to the left hand side } \\[1 em]36-z^2+4z-4 &= 0&& \text{simplify left side} \\[1 em]-z^2+4z+32 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}+4x+32 = 0 $ is a quadratic equation.
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