Question
$$32r^2 = 2$$
Answer
$$ \begin{matrix}r_1 = \dfrac{ 1 }{ 4 } & r_2 = -\dfrac{ 1 }{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 32r^2 &= 2&& \text{move all terms to the left hand side } \\[1 em]32r^2-2 &= 0&& \\[1 em] \end{aligned} $$
$ 32x^{2}-2 = 0 $ is a quadratic equation.
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