$$ \begin{aligned} 3-4y+(-6y)+\frac{37}{5} &= 0&& \text{multiply ALL terms by } \color{blue}{ 5 }. \\[1 em]5\cdot3-5\cdot4y+5(-6y)+5\cdot\frac{37}{5} &= 5\cdot0&& \text{cancel out the denominators} \\[1 em]15-20y-30y+37 &= 0&& \text{simplify left side} \\[1 em]-50y+52 &= 0&& \text{ move the constants to the right } \\[1 em]-50y &= -52&& \text{ divide both sides by $ -50 $ } \\[1 em]y &= \frac{-52}{-50}&& \\[1 em]y &= \frac{26}{25}&& \\[1 em] \end{aligned} $$

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