$$ \begin{aligned} 3-4(2x-1) &= 0&& \text{simplify left side} \\[1 em]3-(8x-4) &= 0&& \\[1 em]3-8x+4 &= 0&& \\[1 em]-8x+7 &= 0&& \text{ move the constants to the right } \\[1 em]-8x &= -7&& \text{ divide both sides by $ -8 $ } \\[1 em]x &= \frac{-7}{-8}&& \\[1 em]x &= \frac{7}{8}&& \\[1 em] \end{aligned} $$
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