Question
$$3-(6-4)+\frac{10}{10}+8-4 = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 3-(6-4)+\frac{10}{10}+8-4 &= 0&& \text{multiply ALL terms by } \color{blue}{ 10 }. \\[1 em]10\cdot3-10\cdot(6-4)+10\cdot\frac{10}{10}+10\cdot8-10\cdot4 &= 10\cdot0&& \text{cancel out the denominators} \\[1 em]30-20+10+80-40 &= 0&& \text{simplify left side} \\[1 em]60 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 60 = 0 } $ is FALSE, we conclude that the equation has no solution.
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