$$ \begin{aligned} \frac{3}{4}x+8 &= 2x-12&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4 \cdot \frac{3}{4}x+4\cdot8 &= 4\cdot2x-4\cdot12&& \text{cancel out the denominators} \\[1 em]3x+32 &= 8x-48&& \text{move the $ \color{blue}{ 8x } $ to the left side and $ \color{blue}{ 32 }$ to the right} \\[1 em]3x-8x &= -48-32&& \text{simplify left and right hand side} \\[1 em]-5x &= -80&& \text{ divide both sides by $ -5 $ } \\[1 em]x &= \frac{-80}{-5}&& \\[1 em]x &= 16&& \\[1 em] \end{aligned} $$

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