$$ \begin{aligned} \frac{3}{4}x+16 &= 2-\frac{1}{8}x&& \text{multiply ALL terms by } \color{blue}{ 8 }. \\[1 em]8 \cdot \frac{3}{4}x+8\cdot16 &= 8\cdot2-8 \cdot \frac{1}{8}x&& \text{cancel out the denominators} \\[1 em]6x+128 &= 16-x&& \text{move the $ \color{blue}{ -x } $ to the left side and $ \color{blue}{ 128 }$ to the right} \\[1 em]6x+x &= 16-128&& \text{simplify left and right hand side} \\[1 em]7x &= -112&& \text{ divide both sides by $ 7 $ } \\[1 em]x &= -\frac{112}{7}&& \\[1 em]x &= -16&& \\[1 em] \end{aligned} $$
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