$$ \begin{aligned} \frac{3}{4}x-2+8 &= 0&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4 \cdot \frac{3}{4}x-4\cdot2+4\cdot8 &= 4\cdot0&& \text{cancel out the denominators} \\[1 em]3x-8+32 &= 0&& \text{simplify left side} \\[1 em]3x+24 &= 0&& \text{ move the constants to the right } \\[1 em]3x &= -24&& \text{ divide both sides by $ 3 $ } \\[1 em]x &= -\frac{24}{3}&& \\[1 em]x &= -8&& \\[1 em] \end{aligned} $$

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