$$ \begin{aligned} \frac{3}{4}(8b+4)-1 &= 4b+14&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4 \cdot \frac{3}{4}(8b+4)-4\cdot1 &= 4\cdot4b+4\cdot14&& \text{cancel out the denominators} \\[1 em]24b+12-4 &= 16b+56&& \text{simplify left side} \\[1 em]24b+8 &= 16b+56&& \text{move the $ \color{blue}{ 16b } $ to the left side and $ \color{blue}{ 8 }$ to the right} \\[1 em]24b-16b &= 56-8&& \text{simplify left and right hand side} \\[1 em]8b &= 48&& \text{ divide both sides by $ 8 $ } \\[1 em]b &= \frac{48}{8}&& \\[1 em]b &= 6&& \\[1 em] \end{aligned} $$

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