Question
$$3(x+2)^2 = 48$$
Answer
$$ \begin{matrix}x_1 = 2 & x_2 = -6 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3(x+2)^2 &= 48&& \text{simplify left side} \\[1 em]3(x^2+4x+4) &= 48&& \\[1 em]3x^2+12x+12 &= 48&& \text{move all terms to the left hand side } \\[1 em]3x^2+12x+12-48 &= 0&& \text{simplify left side} \\[1 em]3x^2+12x-36 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+12x-36 = 0 $ is a quadratic equation.
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